Iron-56 Fission Simulation
Simulation of 56Fe fission into two 28Al nuclei with Q-value calculation
Q-value Calculation:
Fission reaction: 56Fe → 2 28Al
Given masses:
m(56Fe) = 55.93494 u
m(28Al) = 27.98191 u
Q = [m(56Fe) - 2 × m(28Al)] × c²
Q = [55.93494 - 2 × 27.98191] × c²
Q = -0.02888 u × c²
1 u = 931.5 MeV/c²
∴ Q = -0.02888 × 931.5 MeV = -26.90 MeV
The Q-value is negative, so this fission is not energetically possible.
