Power Source

10.0 V

Resistor Values

10.0 Ω
5.0 Ω
5.0 Ω

Simulation Controls

1.0x

Current Measurements

Main Circuit Current (I₁)
0.588 A
Branch AB Current (I₂)
0.235 A
Branch AD Current (I₃)
0.353 A
Bridge Current (I₄)
-0.118 A
Branch BC Current (I₂-I₄)
0.353 A
Branch CD Current (I₃+I₄)
0.235 A

Circuit Analysis

This simulation solves the bridge circuit using Kirchhoff's laws:

Kirchhoff's Voltage Law (KVL)

The sum of all voltages around any closed loop in a circuit must equal zero.

For loop ABDA: 10I₂ + 5I₄ - 5I₃ = 0 ⇒ I₃ = 2I₂ + I₄
For loop BCDB: 5(I₂ - I₄) - 10(I₃ + I₄) - 5I₄ = 0 ⇒ I₂ = 2I₃ + 4I₄

Kirchhoff's Current Law (KCL)

The sum of all currents entering a node must equal the sum of all currents leaving that node.

At node A: I₁ = I₂ + I₃
At node B: I₂ = (I₂ - I₄) + I₄

Solution

Solving these equations simultaneously gives:

I₄ = -2/17 A ≈ -0.118 A
I₃ = 6/17 A ≈ 0.353 A
I₂ = 4/17 A ≈ 0.235 A
I₁ = 10/17 A ≈ 0.588 A