Resistivity of Materials Simulation
This simulation demonstrates how the resistivity of a material affects the resistance of a wire based on its dimensions. The relationship is given by: R = ρL/A, where ρ is resistivity, L is length, and A is cross-sectional area.
Example Problem: A wire of length 15m with cross-section 6.0×10⁻⁷m² has resistance 5.0Ω. The calculated resistivity is 2×10⁻⁷Ω·m.
m
1m
15.0m
30m
m²
1×10⁻⁸m²
6.0×10⁻⁷m²
1×10⁻⁵m²
Ω·m
1×10⁻⁸Ω·m
2.0×10⁻⁷Ω·m
1×10⁻⁵Ω·m
Resistance
5.00
Current Density
8.33×10⁶
Conductivity
5.00×10⁶
Power Dissipation
0.00
