Parallel Plate Capacitor Charging Simulation
Visualize the charging process of a parallel plate capacitor with constant current
centimeters (cm)
Current value:
12 cm
centimeters (cm)
Current value:
5 cm
amperes (A)
Current value:
0.15 A
Physics Principles
This simulation demonstrates the charging of a parallel plate capacitor with a constant current, showing the relationship between charge, potential difference, and displacement current.
The capacitance of parallel plates is given by:
C = ε₀A/d
where ε₀ is the permittivity of free space (8.85×10⁻¹² F/m), A is the plate area (πr²), and d is the plate separation.
The rate of change of potential difference is:
dV/dt = I/C
The displacement current between the plates equals the conduction current in the wires:
I_d = I_c = 0.15 A
Capacitance (C)
80.03 pF
Rate of dV/dt
1.87 ×10⁹ V/s
Conduction Current (I_c)
0.15 A
Displacement Current (I_d)
0.15 A
