Thermal Expansion of a Rectangular Sheet
Example
Question:
Show that the coefficient of area expansion, \(\frac{\Delta A}{A} / \Delta T\), of a rectangular sheet of the solid is twice its linear expansivity, \(\alpha_l\).
Solution:
Consider a rectangular sheet of solid material with length \(a\) and breadth \(b\).
When the temperature increases by \(\Delta T\):
- \(a\) increases by \(\Delta a = \alpha_l a\Delta T\)
- \(b\) increases by \(\Delta b = \alpha_l b \Delta T\)
From the geometry,
\[
\Delta A = \Delta A_1 + \Delta A_2 + \Delta A_3
\]
where \(\Delta A_1 = a\Delta b\), \(\Delta A_2 = b\Delta a\), \(\Delta A_3 = (\Delta a)(\Delta b)\).
Substituting,
\[
\Delta A = a\Delta b + b\Delta a + (\Delta a)(\Delta b)
\]
\[
= \alpha_l a b \Delta T + \alpha_l a b \Delta T + (\alpha_l a\Delta T)(\alpha_l b\Delta T)
\]
\[
= ab[2\alpha_l \Delta T + (\alpha_l \Delta T)^2]
\]
For small \(\alpha_l \Delta T\), \((\alpha_l \Delta T)^2\) is negligible compared to \(2\), so:
\[
\frac{\Delta A}{A} \approx 2\alpha_l \Delta T
\]
Therefore,
\[
\frac{\Delta A}{A} \frac{1}{\Delta T} \approx 2\alpha_l
\]
The coefficient of area expansion is twice the linear expansivity.
About Thermal Expansion
When a rectangular sheet of solid material is heated, both its length and width increase due to thermal expansion. The coefficient of linear expansion (α₁) describes how much the length changes per degree temperature change.
Δb = α₁ × b × ΔT
The area expansion can be calculated by considering the new dimensions (a + Δa) and (b + Δb). The total area change has three components as shown in the simulation.
Mathematical Derivation
The increase in area ΔA has three components:
= a(α₁bΔT) + b(α₁aΔT) + (α₁aΔT)(α₁bΔT)
= 2α₁abΔT + α₁²ab(ΔT)²
Since α₁ is very small (~10⁻⁵ K⁻¹), the second term is negligible compared to the first:
∴ (ΔA/A)/ΔT ≈ 2α₁
This shows the coefficient of area expansion is twice the linear expansivity.



