Correct Answer: A real image beyond 2f

Using the mirror formula: 1/u + 1/v = 1/f

For a concave mirror (f < 0) with object between f and 2f (2f < u < f):

We get 1/2f < 1/v < 0, which means v is negative (real image) and -v > -2f (image beyond 2f).

Why others are wrong:

• Virtual images are formed only when the object is between the pole and focus of a concave mirror.
• Enlarged virtual images occur when the object is inside the focal length.
• A concave mirror always forms an image when an object is placed in front of it.

Correct Answer: A virtual image independent of object location

For a convex mirror (f > 0):

From the mirror formula 1/v = 1/f - 1/u, since u < 0 for real objects, 1/v is always positive, meaning v is always positive (virtual image).

Why others are wrong:

• Convex mirrors cannot form real images as they always diverge light rays.
• Convex mirrors always produce diminished images, never enlarged ones.
• Convex mirrors form images for all real object positions.

Correct Answer: Diminished and located between focus and pole

For a convex mirror (f > 0):

From 1/v = 1/f - 1/u with u < 0, we get v < f.

The image is always virtual, diminished (m < 1), and located between the focus and the pole.

Why others are wrong:

• Convex mirrors never produce enlarged or inverted images.
• There is no position where image size equals object size in convex mirrors.
• Convex mirrors cannot form real images.

Correct Answer: A virtual and enlarged image

For a concave mirror (f < 0) with object between pole and focus (f < u < 0):

From 1/v = 1/f - 1/u, we get v > 0 (virtual image).

Magnification m = -v/u > 1 (enlarged).

Why others are wrong:

• Real images are formed only when object is beyond the focus.
• The image is enlarged, not diminished.
• A concave mirror always forms an image when an object is placed in front of it.