Example

Question:

A pure inductor of 25.0 mH is connected to a source of 220 V. Find the inductive reactance and rms current in the circuit if the frequency of the source is 50 Hz.

Solution:

The inductive reactance, \[ X_L = 2\pi \nu L = 2 \times 3.14 \times 50 \times 25 \times 10^{-3}~\Omega = 7.85~\Omega \] The rms current in the circuit is \[ I = \frac{V}{X_L} = \frac{220~\text{V}}{7.85~\Omega} = 28~\text{A} \]