Wheel Spoke EMF Simulation
A wheel with 10 metallic spokes each 0.5 m long is rotated at 120 rev/min in Earth's magnetic field (HE = 0.4 G). What is the induced emf between the axle and the rim?
\[\varepsilon = \frac{1}{2} \omega B R^2\]
\[= \frac{1}{2} \times 4\pi \times 0.4 \times 10^{-4} \times (0.5)^2\]
\[= 6.28 \times 10^{-5} \, \text{V}\]
Interactive Simulation
Explore how rotation in Earth's magnetic field induces EMF in wheel spokes:
Example
Question:
(a) How does the current in the rotating rod (Example 6.6) change if the frequency is doubled?
(b) What happens to the emf if the radius of the metallic ring is doubled but frequency remains unchanged?
Solution:
(a) The emf generated in the rod is proportional to frequency \(f\) (since \(\omega = 2\pi f\)):
\[
\epsilon = \frac{1}{2} B \omega R^2
\]
If frequency is doubled, \(\epsilon\) doubles; current will also double, assuming resistance stays constant.
(b) If the radius \(R\) is doubled (frequency unchanged), emf increases by a factor of 4 (since \(R^2\) dependence):
\[
\epsilon \propto R^2
\]
If \(R\) is doubled, \(\epsilon\) becomes four times its original value.



