Ammeter Measurement Simulation
This interactive simulation demonstrates Example 4.12, showing how different ammeter types affect current measurement in a circuit with a 3V battery and 3Ω resistor.
Circuit Simulation
Select Ammeter Type:
Measured Current:
Select ammeter type and click calculate
Circuit Analysis:
Total resistance will be calculated based on ammeter type
Current calculation will be shown here
Solution to Example 4.12
Question:
In the circuit (Fig. 4.23) the current is to be measured. What is the value of the current if the ammeter shown
(a) is a galvanometer with a resistance \(R_G = 60.00\,\Omega\);
(b) is a galvanometer described in (a) but converted to an ammeter by a shunt resistance \(r_s = 0.02\,\Omega\);
(c) is an ideal ammeter with zero resistance?
(a) Galvanometer as Ammeter (RG = 60.00Ω):
Total resistance in the circuit:
\[ R_{total} = R_G + 3Ω = 63Ω \]
Current:
\[ I = \frac{3V}{63Ω} = 0.048A \]
(b) Shunted Galvanometer (rs = 0.02Ω):
Resistance of converted ammeter:
\[ \frac{R_G \times r_s}{R_G + r_s} = \frac{60Ω \times 0.02Ω}{(60 + 0.02)Ω} ≈ 0.02Ω \]
Total resistance in the circuit:
\[ R_{total} = 0.02Ω + 3Ω = 3.02Ω \]
Current:
\[ I = \frac{3V}{3.02Ω} ≈ 0.99A \]
(c) Ideal Ammeter (Zero Resistance):
Total resistance in the circuit:
\[ R_{total} = 0Ω + 3Ω = 3Ω \]
Current:
\[ I = \frac{3V}{3Ω} = 1.00A \]



