11th Class Exercise 14.12

Wave on a String Simulation

Wave on a String Simulation

This simulation demonstrates how different points on a string oscillate with the same frequency (60Hz) but different amplitudes and phases, according to the wave equation: y(x,t) = 0.06 sin(2πx/3) cos(120πt)

Animation
Measure Point
Current: 60 Hz
Current: 1x

Key Observations:

  • All points oscillate with the same frequency (60Hz)
  • Points in the same loop have the same phase
  • Amplitude varies along the string according to 0.06 sin(2πx/3)
Current: 0.375 m

Point Measurements:

Amplitude: 0.0424 m

Phase: in phase

Frequency: 60 Hz

Wave Equation: y(x,t) = 0.06 sin(2πx/3) cos(120πt)

Amplitude Function: A(x) = 0.06 sin(2πx/3)

Frequency: ω = 120π rad/s → f = 60Hz

Wavelength: λ = 3 m (from 2π/λ = 2π/3)

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